China DOS Union

The problem comes again. I'm sorry,

The number is put forward. For example, the user inputs a001 & a100.

If it's a number like a001, I need to remove the preceding a00.

If it's a number like a100, I just need to remove a100. The above code can achieve this.

That is to say, there needs to be a judgment on the value input by the user. If the number after the letter is 0, don't take it. Take the number after 0. Like what I said above, for a001, I only take 1. But for other input a100, I need to take 100. This feels relatively difficult.

Originally posted by jmz573515 at 2006-12-28 21:59:
Is there an idea, I wonder if this method can be used when entering the password?

Yes, it can

Originally posted by mouzeming at 2006-12-28 09:08:
Here comes the problem again. Sorry,
The number is put forward. For example, the user enters a001 & a100
If it is a number like a001, I need to remove the a00 in front..
If it is a number like a100, I only ...

@echo off

set "var=abc000123000"

for %%n in (a b c d e f g h i j k l m n o p q r s t u v w x y z) do call set var=%%var:%%n=%%

:loop

if "%var:~0,1%" == "0" set var=%var:~1%&&goto loop

echo %var%

pause

@echo off
setlocal enabledelayedexpansion

set/p aa=Enter your text：

if not defined aa goto :eof
set number=

:loop
if not defined aa goto :e
echo %aa:~0,1%|findstr "[0-9]">nul&&set number=!number!%aa:~0,1%
set aa=%aa:~1%
goto loop
:e
echo !number!
pause