Help me take a look at my code -- to determine a leap year, where is the problem? - China DOS Union Forum

@echo off
set /p year=Please enter the year:
set /a x=%year%%%4
set /a y=%year%%%100
set /a z=%year%%%400
if %x%==0 (
if %y%==0 (
if %z%==0 (
set term=1
) else (
set term=0
)
) else (
set term=1
)
) else (
set term=0
)

Eyes are dazzled!
Re-learning: namejm's "A Notable Issue in the if...else... Statement"
http://www.cn-dos.net/forum/viewthread.php?tid=22704&fpage=1&highlight=if

Modify a bit:

@echo off
set /p year=Please enter the year:
set /a x=%year%%%4
set /a y=%year%%%100
set /a z=%year%%%400
set term=0
if %z% == 0 set term=1
if %x% == 0 (if not %y% == 0 set term=1)

[ Last edited by xycoordinate on 2007-2-28 at 09:04 AM ]

Floor16　xycoordinate	Posted 2007-02-28 21:54
中级用户　Posts 228　Credits 493　From 安徽
@echo off set /p year=Please enter the year: set /a x=%year%%%4 set /a y=%year%%%100 set /a z=%year%%%400 if %x%==0 ( if %y%==0 ( if %z%==0 ( set term=1 ) else ( set term=0 ) ) else ( set term=1 ) ) else ( set term=0 ) Eyes are dazzled! Re-learning: namejm's "A Notable Issue in the if...else... Statement" http://www.cn-dos.net/forum/viewthread.php?tid=22704&fpage=1&highlight=if Modify a bit: @echo off set /p year=Please enter the year: set /a x=%year%%%4 set /a y=%year%%%100 set /a z=%year%%%400 set term=0 if %z% == 0 set term=1 if %x% == 0 (if not %y% == 0 set term=1) [ Last edited by xycoordinate on 2007-2-28 at 09:04 AM ]

Floor17　slore	Posted 2007-02-28 22:51
铂金会员　Posts 2,478　Credits 5,212
The conditions for determining a leap year are: 1. Divisible by 4 but not by 100. 2. Divisible by both 100 and 400. Isn't this contradictory? Can a year divisible by 400 and 100 satisfy the first condition? First judge whether condition 2 is not satisfied, then look at condition 1... Century years must be divisible by 400 to be leap years, while non-century years just need to be divisible by 4.