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Just replace the characters in the first line of A.TXT with the ### characters in B.TXT.
Then replace the characters in the second line of A.TXT with the @@@ characters in B.TXT.
There are several lines that need to be replaced.
........................
Can this work? Please ask experts for guidance.
Thanks!

Last edited by pengfei on 2006-7-22 at 23:19 ]

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@echo off

:: 如果A.txt第M行中含有在第N行中要替换的内容S(M<N)，则会用S来替换B.txt中含有第M行中的匹配内容

:: 例如：假设A.txt中第1行含有在第二行中要替换的@@@，则会用@@@替换B.txt中含有第一行的@@@。

:: 使用格式：要用第M行的内容来替换S，就在第M行的位置上加一句 call :_replace S

:: 如果在第N行上没有要替换的内容，第N行的位置加 set num=N

setlocal enabledelayedexpansion

set num=0

call :_replace ###

call :_replace @@@

set num=3

call :_replace $$$

exit



:_replace

set /a num+=1

set char=%1

for /f "tokens=1,2* delims=:" %%i in ('findstr /n . A.txt') do if %%i equ %num% set str=%%j

for /f "delims=" %%i in (B.txt) do (

    set _str=%%i

    set "_str=!_str:%char%=%str%!"

    echo !_str!>>tmp.txt

)

move tmp.txt B.txt

Referencing the writing of doscc on floor 5, the previous code has been modified. Please note the usage conditions:

@echo off

:: If the content S to be replaced in line N is contained in line M of A.txt (M < N), then the content containing the matching content of line M in B.txt will be replaced with S

:: For example: Suppose line 1 of A.txt contains @@@ that needs to be replaced in line 2, then @@@ will be used to replace @@@ in line 1 of B.txt.

:: Usage format: To use the content of line M to replace S, add a line call :_replace S at the position of line M

:: If there is no content to be replaced on line N, add set num=N at the position of line N

setlocal enabledelayedexpansion

set num=0

call :_replace ###

call :_replace @@@

set num=3

call :_replace $$$

exit



:_replace

set /a num+=1

set char=%1

for /f "tokens=1,2* delims=:" %%i in ('findstr /n . A.txt') do if %%i equ %num% set str=%%j

for /f "delims=" %%i in (B.txt) do (

    set _str=%%i

    set "_str=!_str:%char%=%str%!"

    echo !_str!>>tmp.txt

)

move tmp.txt B.txt

Last edited by namejm on 2006-7-23 at 16:29 ]

Hehe~ I'll give it a try, thanks for your hard work.

@echo off & setlocal enabledelayedexpansion

copy a.txt a-BF.txt >NUL

copy b.txt b-BF.txt >NUL

call :nf @@@

call :nf ###

call :nf $$$

::还有要替换的字符写在这里以 "call :nf 字符" 的型式！注意有特殊意议的字符 如: | & 等...

goto :EOF



:nf

set str=%1

set /P line=<a.txt

more +1 < a.txt >>_a.txt

move /Y _a.txt a.txt



for /f "delims=" %%i in (b.txt) do (

set _str=%%i

set _str=!_str:%str%=%line%!

echo !_str! >>1.txt

)

move /Y 1.txt b.txt

goto :EOF

I'll also give it a try.
Take the three characters @ # $ as an example!
If the file to be processed is more complex. It's best to use a third - party tool!

@echo off & setlocal enabledelayedexpansion

copy a.txt a - BF.txt > NUL

copy b.txt b - BF.txt > NUL

call :nf @@@

call :nf ###

call :nf $$$

::Write the characters that still need to be replaced here in the form of "call :nf character". Note that there are special - meaning characters such as: | &, etc...

goto :EOF



:nf

set str=%1

set / P line = < a.txt

more + 1 < a.txt >> _a.txt

move / Y _a.txt a.txt



for / f "delims=" %%i in (b.txt) do (

set _str = %%i

set _str =!_str:%str% = %line%!

echo!_str! >> 1.txt

)

move / Y 1.txt b.txt

goto :EOF

Last edited by doscc on 2006 - 7 - 23 at 04:38 ]

Re doscc:

　　Your code is really excellent, using the format of call :label parameter. I should learn from you in this regard. After looking at your code, there are some parts that I don't fully understand yet, and I'm gradually figuring them out. Hehe, it's just that my level is limited, so I'll keep figuring it out :）

　　My code seems to be no longer afraid of any sensitive characters except for colons. However, if I need to replace N lines of content, I will inevitably have to repeat the code format for operating the first line of code. Using call to solve it should be a good idea. Someone else can expand on this.

Re namejm & doscc:

Brother doscc implemented line-by-line replacement, while Brother namejm implemented replacement of specified line numbers. Relatively speaking, the former has better flexibility, and the latter has higher efficiency.

For Brother namejm's colon problem, changing tokens=1,2 to tokens=1,2* should solve it. However, this doesn't mean all special character problems can be solved. You'd better find a batch processing code with sufficient scale and complexity (it can also be your own batch processing) as the test text.

In addition, it is suggested to also control the line number as a parameter of :_replace to have greater expandability.

Wow, it works after trying. Our China DOS Union is really full of talented people. But I'm just starting out and I'm completely confused. I hope namejm and doscc brothers can explain the specific meanings and usages of these commands. I'd like to thank you here in advance.

Last edited by pengfei on 2006-7-23 at 13:43 ]

第一行~`!@#$%^&*()-=_+/?>.<,|\

第二行

第三行&

第四行:

第五行

::kkkldnldn##########khldn##k a mnaouoane@@@@@@&&&&44$4$$$$$$$$$><!@#$%^&*()\';,.?/`~|||\<<<>>

sldkla'$$ksoiakpa@@@@@##

sdkoanlkalm@224Y%**8####3&&&&@@@@@

Re willsort:

　　The problem with colons is that using tokens=1,2* works well. It seems that the for statement still needs to be carefully studied; the suggestion to use the line number as a parameter for _replace is a good idea. It's just that I still don't fully understand the format of call :label parameters. I'm still learning from the doscc in building 5. If the moderator has a good method, it's better to post it for us to learn.

　　What I mean by seemingly not being afraid of any sensitive characters means that it seems it can handle whether A.txt or B.txt contains any sensitive characters, not that replacing the content to be replaced like @@@, ### with sensitive characters. Maybe my description was not accurate enough to cause your misunderstanding, or maybe the text I tested was not complex enough to be representative.

　　The text I tested is the following
A.txt

First line~`!@#$%^&*()-=_+/?>.<,|\

Second line

Third line&

Fourth line:

Fifth line

B.txt

::kkkldnldn##########khldn##k a mnaouoane@@@@@@&&&&44$4$$$$$$$$$><!@#$%^&*()\';,.?/`~|||\<<<>>

sldkla'$$ksoiakpa@@@@@##

sdkoanlkalm@224Y%**8####3&&&&@@@@@

Re namejm:

Setting parameters for a specified line number is not difficult. Change set /a num+=1 to set num=%2, and then follow the line number after call :_replace @@@. To write robust code, it is also necessary to perform null checks and type judgments on the introduced parameters. Of course, for module code that is only called internally, this requirement can be appropriately relaxed.

For the issue of resisting special characters, it is suggested that you follow what I said above, save your batch script itself as A.TXt/B.TXT for testing, and I believe you will have many discoveries.

When writing this code, repeatedly testing made my head big; I saved the code I wrote as A.txt/B.txt for testing, oh my god, I didn't even know which was which. Hey, when encountering slightly complicated problems, my mind just short-circuits. It seems that the choice of not studying science and engineering originally wasn't without reason.
　　Any big shot hurry up and come to the rescue吧，I can't take it anymore. hoho.

RE: namejm
The improved code by you is very good. Learning from you! Learning from the moderator!

RE: pengfei
The code is not difficult. The comments are tedious. Please refer to the top-sticked batch processing tutorial. You will understand it soon!

Two brothers' rewritten code completely meets my expected requirements, but I still can't understand it. May I ask, can I directly input characters in the batch processing and then replace the specified strings in the text in sequence? I'll ask for advice in a couple of days. Thanks, everyone.

Last edited by pengfei on 2006-7-23 at 18:41 ]

Excuse me, how to write a batch script that uses SET /P to directly specify a variable %all%, input characters in the batch, and then use this variable to replace the specified characters in a text document.

The batch scripts written by the two elder brothers above, the younger brother still doesn't quite understand, and is studying.

@echo off

setlocal enabledelayedexpansion

set file=

set /p file=  请输入要操作的文件名称(包括扩展名)：

set "file=%file:"=%"

for %%i in ("%file%") do set file=%%~fi

echo.

set replaced=

set /p replaced= 请输入即将被替换的内容：

echo.

set all=

set /p all=  请输入替换字符串：

for /f "delims=" %%i in ('type "%file%"') do (

    set str=%%i

    set "str=!str:%replaced%=%all%!"

    echo !str!>>"%file%"_tmp.txt

)

copy "%file%" "%file%"_bak.txt >nul 2>nul

move "%file%"_tmp.txt "%file%"

start "" "%file%"

```
@echo off
setlocal enabledelayedexpansion
set file=
set /p file= Please enter the name of the file to operate (including extension):
set "file=%file:"=%"
for %%i in ("%file%") do set file=%%~fi
echo.
set replaced=
set /p replaced= Please enter the content to be replaced:
echo.
set all=
set /p all= Please enter the replacement string:
for /f "delims=" %%i in ('type "%file%"') do (
set str=%%i
set "str=!str:%replaced%=%all%!"
echo !str!>>"%file%"_tmp.txt
)
copy "%file%" "%file%"_bak.txt >nul 2>nul
move "%file%"_tmp.txt "%file%"
start "" "%file%"
```