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zouzhxi
中级用户
   蝴蝶之吻
积分 430
发帖 177
注册 2006-9-20 来自 广东深圳
状态 离线
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『第 16 楼』:
使用 LLM 解释/回答一下
如果我输入字母,它还是会出现:
请输入秒数:dddd
0 天 0 小时 0 分 0 秒
请按任意键继续. . .
我是不是来捣乱,,,的...嘻嘻...;)
Last edited by zouzhxi on 2007-1-17 at 09:54 AM ]
If I enter a letter, it still appears:
Please enter the number of seconds: dddd
0 days 0 hours 0 minutes 0 seconds
Press any key to continue...
Am I here to cause trouble,,, hehehe... ;)
Last edited by zouzhxi on 2007-1-17 at 09:54 AM ]
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Butterfly Kiss Blog
计算机DIY联盟论坛 |
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2007-1-17 09:52 |
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PPdos
高级用户
   
积分 783
发帖 268
注册 2006-12-26
状态 离线
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『第 17 楼』:
使用 LLM 解释/回答一下
将以上代码理解为(非毫秒):
set /a D=%t%/86400
set /a H=%t%%%86400/3600
set /a M=%t%%%86400%%3600/60
set /a S=%t%%%86400%%3600%%60
ECHO %D%日%H%时%M%分%S%秒
感悟即:取值为t 除86400秒(等于1日)商为天数 余数除3600秒(等于1小时)商为小时数 余数再循环 以次类推可推广至周月年 但因为32位精确限制将达不到最大预期效果
Understand the above code as (not milliseconds):
set /a D=%t%/86400
set /a H=%t%%%86400/3600
set /a M=%t%%%86400%%3600/60
set /a S=%t%%%86400%%3600%%60
ECHO %D% days %H% hours %M% minutes %S% seconds
The perception is: The value is t divided by 86400 seconds (equal to 1 day), the quotient is the number of days, the remainder is divided by 3600 seconds (equal to 1 hour), the quotient is the number of hours, and the remainder is cycled again, and so on, which can be extended to weeks, months, and years. But due to the 32-bit precision limit, it will not achieve the maximum expected effect
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2007-1-17 11:02 |
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hxuan999
中级用户
   DOS之日
积分 337
发帖 161
注册 2006-11-4
状态 离线
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『第 18 楼』:
使用 LLM 解释/回答一下
Originally posted by namejm at 2007-1-16 16:15:
12楼的代码有如下缺陷:
1、截取小数部分用替换语句是容易出错的,比如:整数部分是小数部分的某一个字符串的时候,如 23.1234。建议不 ...
谢谢指出,呵呵.写的草率了.已经修正了.
Originally posted by namejm at 2007-1-16 16:15:
The code on floor 12 has the following defects:
1. Using a replace statement to intercept the decimal part is error-prone. For example, when the integer part is a certain string of the decimal part, such as 23.1234. It is recommended not ...
Thanks for pointing it out, hehe. It was written carelessly. It has been corrected.
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for /f %%h in (`echo hxuan`) do for /f %%x in (`echo hxuan`) do if %%h==%%x nul |
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2007-1-18 01:55 |
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everest79
金牌会员
      一叶枝头,万树皆春
积分 2564
发帖 1127
注册 2006-12-25
状态 离线
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『第 19 楼』:
使用 LLM 解释/回答一下
Originally posted by PPdos at 2007-1-16 08:39 PM:
各位厉害。。竟然连毫秒都准确到了 。。看来可以修改成春节倒计时了^^
@ECHO OFF&MODE CON COLS=40 LINES=3&TITLE=新年倒计时
SETLOCAL ENABLEDELAYEDEXPANSION
SET /A YEAR=%DATE:~0,4%,MONTH=%DATE:~5,2%,DAY=%DATE:~8,2%
CALL :ALG MONTH %MONTH%&&CALL :ALG DAY %DAY%
IF NOT "%1" == "" SET NB=%1&&GOTO :TOPY
SET /A NX=%RANDOM%%%12+1,NZ=%RANDOM%%%28+1
SET NYY=%NX%.%NZ%
:TOPX
CLS&ECHO.&SET /P NB=%NYY%过年?
IF "%NB%" == "" SET NB=%NYY%&&GOTO TOPZ
IF /I "%NB:~0,1%" == "n" SET NYY=那是什么时候&&GOTO TOPX
IF /I "%NB:~0,1%" == "y" SET NB=%NYY%&&GOTO TOPY
IF NOT "%NB%" == "" SET NYY=%NB%&&GOTO TOPX
:TOPY
ECHO %NB%|FINDSTR /R "^**">nul||GOTO TOPX
FOR /F "tokens=1,2 delims=.:;-/" %%i IN ("%NB%") DO CALL :ALG BM %%i&CALL :ALG BD %%j
IF NOT %BM% GTR 0 (GOTO TOP) ELSE IF %BM% GTR 12 GOTO TOPX
IF NOT %BD% GTR 0 (GOTO TOP) ELSE IF %BD% GTR 31 GOTO TOPX
FOR /L %%i IN (1,1,12) DO (
if %%i geq 8 (set d1=30&&set d2=31) else set d1=31&&set d2=30
set /a st=%%i%%2
if !st! equ 0 (set M%%i=!d2!) else set M%%i=!d1!)
CALL :LM %YEAR%
IF %BM% GTR %MONTH% SET GO=GTR
IF %BM% EQU %MONTH% SET GO=EQU
IF %BM% LSS %MONTH% SET /A NEWYEAR=%YEAR%+1&&SET GO=LSS
GOTO %GO%
:GTR
FOR /L %%i IN (%MONTH%,1,%BM%) DO SET /A DALL=!DALL!+M%%i
SET /A DALL=%DALL%+!M%MONTH%!-%DAY%+%BD%-M%MONTH%-M%BM%
GOTO TIME
:EQU
IF %BD% GTR %DAY% SET /A DALL=%BD%-%DAY%&&GOTO TIME
IF %BD% EQU %DAY% SET DALL=0&&GOTO TIME
IF %BD% LSS %DAY% SET /A NERA=%DAY%-%BD%&&GOTO LSS
:LSS
FOR /L %%i IN (%MONTH%,1,12) DO SET /A OALL+=M%%i
SET /A OALL=%OALL%+!M%MONTH%!-%DAY%-M%MONTH%
CALL :LM %NEWYEAR%
FOR /L %%i IN (1,1,%BM%) DO SET /A NALL+=M%%i
SET /A NALL+=%BD%-M%BM%
SET /A DALL=%OALL%+%NALL%
:TIME
FOR /F "tokens=1-4 delims=:." %%a IN ("%TIME%") DO (
CALL :ALG TT %%b&&CALL :ALG TS %%c&&CALL :ALG TM %%d
SET /A TH=24-%%a-1,TT=60-!TT!-1,TS=60-!TS!-1,TM=1000-!TM!*10
CLS&ECHO/&ECHO 距新年还有%DALL%天!TH!小时!TT!分!TS!秒!TM!毫秒)
IF "%DAY%" == "%DATE:~8,2%" (GOTO TIME) ELSE GOTO END
:END
START /I "" %0 "NB"
GOTO :EOF
:LM
SET /A LM=(%1-2000)%%4
IF NOT %LM% EQU 0 (SET M2=28) ELSE SET M2=29
GOTO :EOF
:ALG
SET CHKALG=%2
IF "%CHKALG:~1,1%" == "" SET %1=%CHKALG%&GOTO :EOF
SET /A %1=%CHKALG:~0,1%*10+%CHKALG:~-1%
GOTO :EOF
我刚写的嘿嘿:D
Originally posted by PPdos at 2007-1-16 08:39 PM:
You guys are amazing. You even got the milliseconds accurate. It seems it can be modified into a Spring Festival countdown^^
@ECHO OFF&MODE CON COLS=40 LINES=3&TITLE=New Year Countdown
SETLOCAL ENABLEDELAYEDEXPANSION
SET /A YEAR=%DATE:~0,4%,MONTH=%DATE:~5,2%,DAY=%DATE:~8,2%
CALL :ALG MONTH %MONTH%&&CALL :ALG DAY %DAY%
IF NOT "%1" == "" SET NB=%1&&GOTO :TOPY
SET /A NX=%RANDOM%%%12+1,NZ=%RANDOM%%%28+1
SET NYY=%NX%.%NZ%
:TOPX
CLS&ECHO.&SET /P NB=%NYY%过年?
IF "%NB%" == "" SET NB=%NYY%&&GOTO TOPZ
IF /I "%NB:~0,1%" == "n" SET NYY=Then when is it&&GOTO TOPX
IF /I "%NB:~0,1%" == "y" SET NB=%NYY%&&GOTO TOPY
IF NOT "%NB%" == "" SET NYY=%NB%&&GOTO TOPX
:TOPY
ECHO %NB%|FINDSTR /R "^**">nul||GOTO TOPX
FOR /F "tokens=1,2 delims=.:;-/" %%i IN ("%NB%") DO CALL :ALG BM %%i&CALL :ALG BD %%j
IF NOT %BM% GTR 0 (GOTO TOP) ELSE IF %BM% GTR 12 GOTO TOPX
IF NOT %BD% GTR 0 (GOTO TOP) ELSE IF %BD% GTR 31 GOTO TOPX
FOR /L %%i IN (1,1,12) DO (
if %%i geq 8 (set d1=30&&set d2=31) else set d1=31&&set d2=30
set /a st=%%i%%2
if !st! equ 0 (set M%%i=!d2!) else set M%%i=!d1!)
CALL :LM %YEAR%
IF %BM% GTR %MONTH% SET GO=GTR
IF %BM% EQU %MONTH% SET GO=EQU
IF %BM% LSS %MONTH% SET /A NEWYEAR=%YEAR%+1&&SET GO=LSS
GOTO %GO%
:GTR
FOR /L %%i IN (%MONTH%,1,%BM%) DO SET /A DALL=!DALL!+M%%i
SET /A DALL=%DALL%+!M%MONTH%!-%DAY%+%BD%-M%MONTH%-M%BM%
GOTO TIME
:EQU
IF %BD% GTR %DAY% SET /A DALL=%BD%-%DAY%&&GOTO TIME
IF %BD% EQU %DAY% SET DALL=0&&GOTO TIME
IF %BD% LSS %DAY% SET /A NERA=%DAY%-%BD%&&GOTO LSS
:LSS
FOR /L %%i IN (%MONTH%,1,12) DO SET /A OALL+=M%%i
SET /A OALL=%OALL%+!M%MONTH%!-%DAY%-M%MONTH%
CALL :LM %NEWYEAR%
FOR /L %%i IN (1,1,%BM%) DO SET /A NALL+=M%%i
SET /A NALL+=%BD%-M%BM%
SET /A DALL=%OALL%+%NALL%
:TIME
FOR /F "tokens=1-4 delims=:." %%a IN ("%TIME%") DO (
CALL :ALG TT %%b&&CALL :ALG TS %%c&&CALL :ALG TM %%d
SET /A TH=24-%%a-1,TT=60-!TT!-1,TS=60-!TS!-1,TM=1000-!TM!*10
CLS&ECHO/&ECHO There are %DALL% days!TH! hours!TT! minutes!TS! seconds!TM! milliseconds until New Year)
IF "%DAY%" == "%DATE:~8,2%" (GOTO TIME) ELSE GOTO END
:END
START /I "" %0 "NB"
GOTO :EOF
:LM
SET /A LM=(%1-2000)%%4
IF NOT %LM% EQU 0 (SET M2=28) ELSE SET M2=29
GOTO :EOF
:ALG
SET CHKALG=%2
IF "%CHKALG:~1,1%" == "" SET %1=%CHKALG%&GOTO :EOF
SET /A %1=%CHKALG:~0,1%*10+%CHKALG:~-1%
GOTO :EOF
I just wrote this hehe :D
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2007-1-18 07:15 |
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uiopuiop
中级用户
  
积分 400
发帖 211
注册 2007-9-30
状态 离线
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『第 20 楼』:
使用 LLM 解释/回答一下
有办法突破11天的限制吗?如果数字太大会溢出啊,多谢!
请输入秒数(退出请直接按回车):4321432531252
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
11 天 32 小时 19 分 47 秒
Is there a way to break through the 11-day limit? If the number is too large, it will overflow. Thanks!
Please enter the number of seconds (press Enter directly to exit): 4321432531252
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
11 days 32 hours 19 minutes 47 seconds
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2007-10-5 10:21 |
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uiopuiop
中级用户
  
积分 400
发帖 211
注册 2007-9-30
状态 离线
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『第 21 楼』:
这个方法好点
使用 LLM 解释/回答一下
这个论坛果然不错!!! 强烈支持!
@echo off
:begin
cls
echo.
set input=
set /p input= 请输入秒数(退出请直接按回车):
if not defined input exit
set /a SS=%input%%%60
set /a MM=%input%/60%%60
set /a HH=%input%/3600%%60
if %HH% GEQ 24 set /a HH=HH%%24
set /a DD=%input%/86400
if %DD% GEQ 7 set /a DD=DD%%7
set /a WW=%input%/604800%%60
echo.
if %DD% GEQ 1 (echo %WW% 周 %DD% 天 %HH% 小时 %MM% 分 %SS% 秒
) else (
echo %DD% 天 %HH% 小时 %MM% 分 %SS% 秒
)
echo.
pause
goto begin
Last edited by uiopuiop on 2007-10-5 at 11:28 AM ]
This forum is really good!!! Strongly support!
@echo off
:begin
cls
echo.
set input=
set /p input= Please enter the number of seconds (press Enter directly to exit):
if not defined input exit
set /a SS=%input%%%60
set /a MM=%input%/60%%60
set /a HH=%input%/3600%%60
if %HH% GEQ 24 set /a HH=HH%%24
set /a DD=%input%/86400
if %DD% GEQ 7 set /a DD=DD%%7
set /a WW=%input%/604800%%60
echo.
if %DD% GEQ 1 (echo %WW% weeks %DD% days %HH% hours %MM% minutes %SS% seconds
) else (
echo %DD% days %HH% hours %MM% minutes %SS% seconds
)
echo.
pause
goto begin
Last edited by uiopuiop on 2007-10-5 at 11:28 AM ]
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2007-10-5 10:27 |
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uiopuiop
中级用户
  
积分 400
发帖 211
注册 2007-9-30
状态 离线
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『第 22 楼』:
使用 LLM 解释/回答一下
不过。。。。。
请输入秒数(退出请直接按回车):65356534654
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
29 周 25 天 10 小时 33 分 20 秒
However...
Please enter the number of seconds (press Enter directly to exit): 65356534654
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
Invalid number. Numbers are limited to 32-bits of precision.
29 weeks 25 days 10 hours 33 minutes 20 seconds
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2007-10-5 10:33 |
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uiopuiop
中级用户
  
积分 400
发帖 211
注册 2007-9-30
状态 离线
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『第 23 楼』:
算法有误
使用 LLM 解释/回答一下
请输入秒数(退出请直接按回车):3431253
5 周 4 天 5 小时 7 分 33 秒
好像因该时17小时,不是5小时。。。。
Last edited by uiopuiop on 2007-10-5 at 12:04 PM ]
Please enter the number of seconds (press Enter directly to exit): 3431253
5 weeks 4 days 5 hours 7 minutes 33 seconds
It seems it should be 17 hours, not 5 hours...
Last edited by uiopuiop on 2007-10-5 at 12:04 PM ]
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2007-10-5 11:53 |
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scriptor
银牌会员
    
积分 1187
发帖 555
注册 2006-12-21
状态 离线
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2007-10-5 12:25 |
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uiopuiop
中级用户
  
积分 400
发帖 211
注册 2007-9-30
状态 离线
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『第 25 楼』:
使用 LLM 解释/回答一下
你的算法很好,小弟愚笨,如何输入以秒为单位的数字,输出只要精确到秒就可以了。并且代码在一个批处理里。
能不能写出来,万分感激!
Last edited by uiopuiop on 2007-10-5 at 12:54 PM ]
Your algorithm is very good, I am stupid. How to input a number in seconds and output it with precision to seconds only. And the code is in a batch file.
Can you write it out, thank you very much!
Last edited by uiopuiop on 2007-10-5 at 12:54 PM ]
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2007-10-5 12:29 |
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