中国DOS联盟

有这样的文件名:
ab00091_902111.bmp
xx00091_322322.xml
xss0092_dddddd.bmp
xxxxx92_fdddffff.xml
www93_dddssbf.bmp
sssfff93djjfffddd.xml

他们的共同点是 91,92,93

我想同时更改其名为
123a.bmp
123a.xml
123b.bmp
123b.xml
123c.bmp
123c.xml

请各位帮忙.

一个取巧的方法。

@echo off

for /f "delims=" %%i in ('dir/b *.bmp *.xml^|sort /+8') do (for %%a in (a b c) do ren %%i 123%%a%%~xi)2>nul

@echo off

setlocal enabledelayedexpansion

set var=abc

for /f "delims=" %%i in ('dir /b *.bmp *.xml') do (

	for /l %%a in (91,1,93) do (

		set /a l=%%a-91

		echo %%i|find "%%a">nul && call :label "%%i" %%a !l! %%~xi

	)

)

pause

:label %1 %2 %3 %4

echo ren %1 "%2!var:~%3,1!%4"

goto :eof

方法太笨速度超慢~~

@echo off

for %%L in (91.a 92.b 93.c) do (

  for %%F in (*%%~nL*.bmp *%%~nL*.xml) do (

    set var=%%~xL

    call ren "%%F" "123%%var:~1%%%%~xF"

  )

)

谢谢各位！！！真没想到批处理竟然如此强大。