中国DOS联盟

@echo off

setlocal enabledelayedexpansion

::::::::::::::::::::::::::::Find The Biggest Public Divisor::::::::::::::::::::::::::::

::::::::::::::::::::::::::::       {s11ss  2007-9-21}       ::::::::::::::::::::::::::::

:r

echo Please input two integers,like 9,21:

set /p n=

echo.

echo Calculating...

set /a i=1

for %%a in (!n!) do (

	set n!i!=%%a

	set /a i+=1

)

if !n1! equ !n2! (

	call :e !n1!

	goto :eof

)

if !n1! lss !n2! (

	set t=!n1!

	set n1=!n2!

	set n2=!t!

)

set /a big=!n1!

set /a small=!n2!

:c

set /a remain=!big!%%!small!

if !remain! equ 1 (

	echo.

	echo They don't have the public divisor.

	goto :e

)

if !remain! equ 0 (

	echo.

	echo The biggest public divisor is !small!.

	goto :e

) else (

	set big=!small!

	set small=!remain!

	goto :c

	)

:e

echo.

echo Press Any Key To Exit...

pause>nul

LZ的代码似乎有些长，发一段代码，支持求若干个数字之间的公约数

@echo off 2>nul 3>nul& setlocal enabledelayedexpansion

echo 请输入几个整数，类似：21 7 14

set /p n=

set num2=%n:* =%

for %%i in (%n%) do call :test %%i !num2!

echo 它们的公约数为：%num2%



pause>nul

:test %num1% %num2%

set /a temp=%1 %% %2

if %temp% NEQ 0 (

      set/a num1=%2,num2=%temp%

      call :test !num1! !num2!) else set num2=%2

Last edited by youxi01 on 2007-9-21 at 01:43 PM ]