我想把一个文件夹下多个文本，按30行来拆分，并保存在指定的文件夹里，并用原文件名命名。
比如：文件夹里有a.txt、b.txt、c.txt....把他们按30行来分割，保存在d：\wj里，并命名为a1.txt、a2.txt、a3.txt....b1.txt、b2.txt...c1.txt、c2.txt....如何实现？

a.txt 按30行一个文件拆分为a1.txt、a2.txt、a3.txt ？

是的

我也想知道这个...
要是能按分章节拆分的话更好...

Usage: split.exe ]
Output fixed-size pieces of INPUT to PREFIXaa, PREFIXab, ...; default
PREFIX is `x'. With no INPUT, or when INPUT is -, read standard input.

-b, --bytes=SIZE put SIZE bytes per output file
-C, --line-bytes=SIZE put at most SIZE bytes of lines per output file
-l, --lines=NUMBER put NUMBER lines per output file
-NUMBER same as -l NUMBER
--verbose print a diagnostic to standard error just
before each output file is opened
--help display this help and exit
--version output version information and exit

SIZE may have a multiplier suffix: b for 512, k for 1K, m for 1 Meg.

Report bugs to <bug-textutils@gnu.org>.


附件无法上传.咋办

google搜索“UnxUtils”
里面有split

能满足否?

@echo off&setlocal enabledelayedexpansion
for /f "delims=" %%i in ('dir /b /a-d "*.txt" 2^>nul') do (
set id=1
set num=
for /f "tokens=1,* delims=:" %%a in ('findstr /n .* "%%i"') do (
set/A num+=1
echo/%%b>>"d:\wj\%%~ni!id!.txt"
if !num! GEQ 30 set/A id+=1&set num=
)
)
pause

通过for计数输出会忽略空行，原来讨论过这个问题，好像没办法，否则代码太烦琐，过大文本太慢

找到一个方法

SETLOCAL ENABLEDELAYEDEXPANSION

for /f "delims=" %%a in ('dir /b *.txt') do (

    for /f "skip=2 tokens=1* delims=" %%b in ('find /v /n "" "%%a"') do (

        set /a num=%%b/30+1

        echo.%%c>>"%%~dpna!num!%%~xa"

    )

set num=

)