例如 C:\1\2\3\4有四层
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怎么获得路径的层数呀?
标题：怎么获得路径的层数呀?
@echo off
set file=c:\ab c\def\gh\cd
set count=0
:loop
if "%file:~-1%"=="\" set /a count+=1
set "file=%file:~0,-1%"
if not "%file%" == "" goto loop
echo count=%count%
pause
[ Last edited by halulove on 2007-8-20 at 10:39 AM ]
set file=c:\ab c\def\gh\cd
set count=0
:loop
if "%file:~-1%"=="\" set /a count+=1
set "file=%file:~0,-1%"
if not "%file%" == "" goto loop
echo count=%count%
pause
[ Last edited by halulove on 2007-8-20 at 10:39 AM ]
其实这个问题论坛里有很多讨论了，也有很多的方法，楼上的也不错啊
@echo off
set "file=c:\ab c\def\gh\cd"
call :getpath "%file%"
echo 共有：%count%层
pause>nul
:getpath
for /f "delims=\ tokens=1,*" %%i in ("%~1") do (
if "%%i"=="%~1" goto :eof
set/a count+=1
call :getpath "%%j")
VBS:
file = "c:\ab c\def\gh\cd"
MsgBox UBound(Split(file,"\"))
file = "c:\ab c\def\gh\cd"
MsgBox UBound(Split(file,"\"))
slore 兄的算法太牛了！！很简便！！
来源：https://www.cn-dos.net/forum/viewthread.php?tid=32933 · 打印时间 2026-08-05 15:03