作者:heicai | 时间:2007-06-29 11:33 | 标题:想获取某个服务的路径出了问题
@echo off
for /f "skip=4 tokens=3" %%i in ('reg QUERY HKEY_LOCAL_MACHINE\SYSTEM\ControlSet001\Services\AVP /v ImagePath
') do (echo %%i)
pause
我卡巴在服务里的路径是"C:\Program Files\Kaspersky Lab\Kaspersky Anti-Virus 6.0\avp.exe" -r
我用reg QUERY HKEY_LOCAL_MACHINE\SYSTEM\ControlSet001\Services\AVP /v ImagePath
命令查看时想只回显输出"C:\Program Files\Kaspersky Lab\Kaspersky Anti-Virus 6.0\avp.exe"
部分,不知道我上面的代码该如何修改才能成功
作者:heicai | 时间:2007-06-29 11:34
C:\Documents and Settings\Administrator>reg QUERY HKEY_LOCAL_MACHINE\SYSTEM\Cont
rolSet001\Services\AVP /v ImagePath
! REG.EXE VERSION 3.0
HKEY_LOCAL_MACHINE\SYSTEM\ControlSet001\Services\AVP
ImagePath REG_EXPAND_SZ "C:\Program Files\Kaspersky Lab\Kaspersky Anti-V
irus 6.0\avp.exe" -r
作者:heicai | 时间:2007-06-29 11:41
@echo off
for /f "skip=4 tokens=3-7" %%i in ('reg QUERY HKEY_LOCAL_MACHINE\SYSTEM\ControlSet001\Services\AVP /v ImagePath
') do (echo %%i %%j %%k %%l %%m)
pause
自己已解
作者:lxmxn | 时间:2007-06-29 11:44
Try 1 try
@echo off
for /f "delims=skip=4 tokens=3" %%i in ('reg QUERY HKEY_LOCAL_MACHINE\SYSTEM\ControlSet001\Services\AVP /v ImagePath
') do (echo %%i|sed "s/.*\(\".*\"\).*/\1/")
pause
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