@echo off
set str=0123456789
cd.>result.txt
setlocal enabledelayedexpansion
for /l %%i in (0,1,7) do (
set /a num1=%%i+1
for /l %%j in (!num1!,1,8) do (
set /a num2=%%j+1
for /l %%k in (!num2!,1,9) do (
set /a count+=1
echo !str:~%%i,1!!str:~%%j,1!!str:~%%k,1!>>result.txt
)
)
)
echo 各个数位上的数字互不相同,且组成该数的数字与其他数中的数字不完全相同的三位数有 %count% 个>>result.txt
start result.txt