做了一个sql server存储过程的批处理，有个问题请教
读取a.txt :

POLICENO varchar(10) *
PNAME varchar(10)
ISADMIN char(2)
PASSWD varchar(20)
UNITID varchar(9)
MOBILE varchar(20)
PHONE varchar(20)
EMAIL varchar(20)
WADDRESS varchar(50)
HADDRESS varchar(50)
MEMO varchar(100) end

输出为b.txt :

@POLICENO varchar(10),
@PNAME varchar(10),
@ISADMIN char(2),
@PASSWD varchar(20),
@UNITID varchar(9),
@MOBILE varchar(20),
@PHONE varchar(20),
@EMAIL varchar(20),
@WADDRESS varchar(50),
@HADDRESS varchar(50),
@MEMO varchar(100),

批处理命令是：

for /f "tokens=1,2" %%a in (.\databaseinfo\%filename%.txt) do @echo @%%a %%b, >> .\%filename%\upAdd%filename%.txt

现在想去掉b.txt中最后一行末尾的的“，”或者在输入b.txt时最后一行没有”，“
因为存储过程最后一行不能有“，”，而其他行末尾是必须的。
希望高手给代码能解释一下，好认真学习，谢谢大家！！！

@echo @%%a %%b,
你把最后的,号去掉不就可以了么????

我只是要去掉最后一行那一个逗号， 改怎么做？

Last edited by windad on 2007-10-4 at 11:58 AM ]

发一最笨的方法,呵呵

@echo off

for /f "tokens=1,2" %%i in ('findstr /v /c:"MEMO" "a.txt"') do echo @%%i %%j,

>>b.txt
for /f "tokens=1,2" %%i in ('findstr /c:"MEMO" "a.txt"') do echo @%%i %%j >>b.txt

Originally posted by waynebeat at 2007-10-4 12:48 PM:
发一最笨的方法,呵呵

@echo off

for /f "tokens=1,2" %%i in ('findstr /v /c:"MEMO" "a.txt"') do echo @%%i %%j,

>>b.txt
for /f "tokens=1,2&q ...

“MEMO”是变化的时候怎么办那？a.txt内容全部是可变的呢？
谢谢

@echo off



rem 取得最后一行的行号:

for /F "tokens=1 delims=:" %%a in ('findstr /n . a.txt') do set totalnum=%%a



(for /f "tokens=1-3 delims=: " %%a in ('findstr /n . a.txt') do (

    if %%a equ %totalnum% (echo %%b %%c) else (echo %%b %%c,)

))>b.txt

看懂了，谢谢斑竹呀！！！

Originally posted by lxmxn at 2007-10-4 03:36 PM:

@echo off



rem 取得最后一行的行号:

for /F "tokens=1 delims=:" %%a in ('findstr /n . a.txt') do set totalnum=%%a



(for /f "tokens=1-3 delims=: " %%a in ('find ...