中国DOS联盟

ROBOCOPY log ------------------------------------------------------------------------------- ROBOCOPY :: Robust File Copy for Windows :: Version XP010 ------------------------------------------------------------------------------- Started : Sat Oct 02 22:47:20 2010 Source = R:\lftp\ Dest = R:\-10-02\ Files : *.* Options : *.* /FP /NS /NDL /L /S /E /COPY:DAT /PURGE /MIR /NP /R:1000000 /W:30 ------------------------------------------------------------------------------ Newer R:\lftp\lftp-install.txt New File R:\lftp\lftp-install.txt.bak ------------------------------------------------------------------------------ Total Copied Skipped Mismatch FAILED Extras Dirs : 2 0 2 0 0 0 Files : 11 2 9 0 0 0 Bytes : 1.81 m 5.4 k 1.81 m 0 0 0 Times : 0:00:00 0:00:00 0:00:00 0:00:00 Ended : Sat Oct 02 22:47:20 2010

@echo off for /f "tokens=2* delims=R" %%i in ('findstr /i "New" robocopy.log') do echo R%%i%%j pause

显示的结果是 两条记录 Newer R:\lftp\lftp-install.txt New File R:\lftp\lftp-install.txt.bak 怎么才能方便的显示出来总共有两条新记录？

@echo off for /f "tokens=2* delims=R" %%i in ('findstr /i "New" robocopy.log') do （echo R%%i%%j echo 总共%N%t条记录 ) pause

我网上看到一段代码计数的。但是试了几次无法和上面这段结合起来 老是出错 谁能帮帮我 @echo off for /l %%a in (1,1,10) do (call :abc %%a) goto :eof :abc set "v=%~1" echo %v% pause goto :eof 谢谢

@echo off for /f "tokens=2* delims=R" %%i in ('findstr /i "New" robocopy.log') do （echo R%%i%%j call :abc ) goto :eof echo 总共%N%条记录 pause :abc set "N=%~1" echo %N% pause goto :eof

知道了。。。。。。。 set a=0 for /f "tokens=2* delims=R" %%i in ('findstr /i "New" robocopy.log') do （ set /a a+=1 ) echo %a% files been updated