中国DOS联盟

有N个字符作为特征码

某文件内可能含有这N个字符,如何判断文件内是否出现这些字符中的"任意一个"

逐个"find 字符 文件"太慢了,如果特征码太多速度很慢

sed -e '/AAA/b' -e '/BBB/b' -e '/CCC/b' -e d test.txt&& echo %time%
命令可以一次查找多个字符,但返回的结果无法判定是否包含字符
如果文件不包含这些字符也会一样显示%time%,该怎么写呢

还有别的工具能实现这个功能吗:)

下面放搜索的字串
sed.ini:

AAA
BBB
CCC

findstr /g:sed.ini YourFileToSearch

@echo off&setlocal EnableDelayedExpansion

set xs=0

set "var=sed -e "{s/aaa//;s/bbb//;s/ccc//g}" a.txt"

for /f "tokens=1* delims=:" %%a in ('findstr /n .* a.txt') do set num%%a=%%b

for /f "delims=" %%a in ('%var%') do (

  set /a str+=1

  call set uew=%%num!str!%%

  if "!uew!"=="%%a" set /a xs=1

)

echo 共有 !xs! 行含有指定字符.

pause

Originally posted by lxmxn at 2007-10-16 23:26:
下面放搜索的字串
sed.ini:

findstr /g:sed.ini YourFileToSearch

sed.ini只放一行内容有效

多行无效??

Originally posted by 26933062 at 2007-10-16 23:55:

@echo off&setlocal EnableDelayedExpansion

set xs=0

set "var=sed -e "{s/aaa//;s/bbb//;s/ccc//g}" a.txt"

for /f "tokens=1* delims=:" %%a in ('findstr /n . ... 




只能统计第一个特征码，文件中包含bbb/ccc无法统计出来:o

看来只有运行3次sed了.不知道效率如何
每次替换一种字符.

Originally posted by zerocq at 2007-10-17 00:27:


sed.ini只放一行内容有效

多行无效??

我测试多行有效。

G:\>type sed.ini
perl
sed
first

G:\>type test.txt
this is a perl test
something to use sed
www.cn-dos.net/forum
my first important filter is the Great GNU sed
javascript

G:\>findstr /g:sed.ini test.txt
this is a perl test
something to use sed
my first important filter is the Great GNU sed

G:\>

Last edited by lxmxn on 2007-10-17 at 01:48 AM ]

请问版主用的是什么操作系统??

问题已搞定,可以结贴了

用egrep.exe可以支持同时搜索多个字符,用|来分隔字符

而且正常返回%errorlevel%

我的OS是Windows XP。