中国DOS联盟

实例如下： @echo off & set VAL=10& set Z=VAL echo %Z% echo %%Z%% echo %%%Z%%% echo %%%%Z%%%% echo %%%%%Z%%%%% call echo %Z% call echo %%Z%% call echo %%%Z%%% call echo %%%%Z%%%% call echo %%%%%Z%%%%% gives the following output (only the line 'call echo %%%Z%%%' gives me what I originally wanted): - VAL %Z% %VAL% %%Z%% %%VAL%% VAL VAL 10 %Z% %VAL% And running the echo commands from test.bat at the command prompt gives: - VAL %VAL% %%VAL%% %%%VAL%%% %%%%VAL%%%% VAL 10 %10% %%10%% %%%10%%% 现在想问的问题是：在用CALL调用内部命令ECHO的时候要脱掉一个%符号，但是echo命令在显示%符号的时候是双%%显示为单%，4个%显示为双%，想问一下两者先考虑哪个？也就是说是先执行call的脱掉%字符？还是先脱掉echo显示%符号的脱掉，从以上实例可以看出先是脱掉ECHO进行显示的%符号脱掉，呵呵，大家细细琢磨吧，很绕人的，^_^......... [ Last edited by bagpipe on 2006-8-21 at 15:51 ]